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Student Before 2. Five sophomores were given an English achievement test before and after receiving instruction in basic grammar. Their scores are shown below. Using the .05 level, does the experimental memory improvement therapy make a difference? 88888 la. Identify the populations 1b. Restate the question as a research hypothesis and null hypothesis about the populations. 2. Determine the characteristics of the comparison distribution. 3. Determine the cutoff sample score on the comparison distribution at which the null hypothesis should be rejected. 4. Determine your sample's score on the comparison distribution. 5a. Decide whether or not to reject the null hypothesis. 5b. Compute the effect size. 5c. State your decision in the American Psychological Association (APA) Form

Answer 1

Sample #1	Sample #2	difference , Di =sample1-sample2	(Di - Dbar)²
20	30	-10.00	36.00
30	50	-20.00	256.00
20	10	10.00	196.00
40	30	10.00	196.00
30	40	-10.00	36.00

	sample 1	sample 2	Di	(Di - Dbar)²
sum =	140	160	-20.000	720.000

Ho :   µd=   0                  
Ha :   µd ╪   0                  
                          
Level of Significance ,    α =    0.05       claim:µd=0          
                          
sample size ,    n =    5                  
                          
mean of sample 1,    x̅1=   28.000                  
                          
mean of sample 2,    x̅2=   32.000                  
                          
mean of difference ,    D̅ =ΣDi / n =   -4.000                  
                          
std dev of difference , Sd =    √ [ (Di-Dbar)²/(n-1) =    13.4164                  
                          
std error , SE = Sd / √n =    13.4164   / √   5   =   6.0000      
                          
t-statistic = (D̅ - µd)/SE = (   -4   -   0   ) /    6.0000   =   -0.667
                          
Degree of freedom, DF=   n - 1 =    4                     
                          
p-value =        0.541470   [excel function: =t.dist.2t(t-stat,df) ]               
Conclusion:     p-value>α , Do not reject null hypothesis         

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