Question

in inches 42 09474- xonna towwes op - Christmas Nut V 3-0137 - 200 SHEETS - FILLER ooood takes 1500 eb to crake the Nut What is F = Point G is 2" post point B on B-D-F what are the internal loods at G 1 Axial P= Shear v= Moment M = Point it is 2" past A on A-C what are the internal loods at H Axial Pa shear va Moment M=

Answer 1

Using the method of Virtual work. Refer to the handwritten solution.

fBD of BD By = of Busca (By symmetry) - Br = F Efnao Etye — Бх - Вя > At point - Axial G- force, P = carda & P = 489.33 x 0.89 Te = 217.75 lb) Shear fore, va & sinde 489,33_x_only lv = 58.72 lb Moment, M- & Sindy 2". M = 117.44 eb.in

B(-6,3) iy The ,) ((-6,-3) Step 1 - Taking osigin Points at D and defining condita supe. Gaing visterd work_pzincipdte loethed Step 3 - Dixplece point A by sn in left direction. This will increase then by & and will decrease y by sy. Stepy - writing y and a in terms of u anda ms_AB_Co. On + BD.comn y Di 300m ex-CAB Bino, 82.) +EBD Sin O $0.) S. DE C . 61 ALO, AB sino, BD sinda . AB Cast, so = BD Corte & de S2, BD 630282 Casa Sms | AB sino BD desde cou) + (-8D_Bin da ile) - coshi - (AB x BD fand, casta 88 + 8D sinde) sda Steps - writing virtual FSX + 2.684) + ?(Sy) fxon t2 work dur to e forse FLP din direction?

Fl. (MBXQD stand, could + D300,250] + + 2PC DOO 801) Doplnky t t a PDL Code A B x BD tano, cosda + BD sind ing values DE A B = BD , P = 1500 lb 14921013 : J17 (s)² + (3)= 34 (672 +(37² = 545 Cad. 6 Jus -0.89, tand: 3:0.6, Sind o w Tf. 489.33 16 - Moking FBD of AC Efx0 QAY DIE-CAF OO y 17 of sire, Cu At Point H Arical force = & Costi Te = 209.8 16 Co., 3 - Coso, 134 Cool 0.85 sind, 2 0.51 Shear force 1 ( & sinda 105.888b Moment M. TM- 251,76 lb. in & find, x L a