Question

(**) In #5-#6, find all solutions of under determined linear system by using the row operations: (2. 0:01 (0.21 -4.02 +2.13 +24 +02 -13 +2.04 +0.02 +0x3 +344 = 11 = 5 = 9 2 0.0 ( 0.1 +2.02 +02 0.02 -13 -4.03 0.13 +0.04 +3.25 +0.04 +45 + +2:05 = 7 = -1 = 1

Answer 1

22,-472 +233 +24=11 Oui+22 - 23+274-5 oni +012+ 013+3N4-9 of Augmented matrix [ 2-4 21:41 To 1 -12'5 - - - - - w R> 士F, Rz7 ŹR3 [-2 I / ! "/27 To 0 -12 is Looo Olsd Hore matrix has pivot column in ist and and 4th Column flere az is free variable n, -212 +13 + 14 de la M₂-83+2014=5 H2 = 83-1 n4=3 let azt a = b +222-23 - 12*470= 2+13 mg = R3-1 = #1 *3=7, na=3 2 = 2+t 7 T 27 wo I +1-9

ni+212 - Aztona +325 T on 1+02-403 tona tas-1 on, ton2tong that aast Augmented matrix r0 2 -1 0 3:57 0 (0) -4 o 11-1 oo 0 0211 Hlore est, and and the Column has hi - pirote fee therepre az=t, ng=s are sooviable therefore, n =-202+23-325 +5 n2= . . +4n3o.xs-1 na = -235 24 = 1–28, 2 = 48-3-| n =-2 (4t-5-1) ++ 38+5 ,57 -74-s M- 7 -77cd M2 = -1 +90-s n = 4 1- 24 na = ng=s 7. I Itt TON