Question

C++ Program. Thanks

Assume a Node class has been defined using the Node class implementation in your textbook, except that the data members have been declared public instead of private. This means that the code shown below has direct access to the data members defined inside the Node class. Type the EXACT output of the following code segment. You may assume that the code compiles and executes without errors. Node<char> *ptr1; Node<char> *ptr2; Node<char> *top; char ch; ptr1 = new Node<char>; top = ptr1; ptr 1->item = 'S'; ptr1 = = new Node<char>; top->next = ptr1; ptr 1->item = 'R'; for (ch = 'G'; ch >= 'B'; ch--) { ptr2 = new Node<char>; ptr 1->next = ptr2; ptr2->item = ch; ptr 1 = ptr 1 ->next; ww ptr1->next = nullptr; ptr2 = top->next; ptr2 = ptr2->next; ptr 1 = ptr2->next; ptr1 = ptr1->next; cout << ptr 1->item << " "; cout << ptr2->item << ""'; ptr2 = ptr2->next; ptr1 = top->next; cout << ptr 1->item << ""; cout << ptr2->item << ""; cout << top->item << endl; [11]

Answer 1

The output for the above program is:

E G R F S

The linked list created is:

GI & Epic BI NOLU q top

The above code will make prt2 to point to the node with value G and prt1 points to node with value E. So, E and G are printed first.

ptr2 = top->next; ptr2 = ptr 2->next; ptr 1 = ptr2->next; ptr 1 = ptr 1->next;

ptr2 = ptr 2->next; ptr 1 = top->next; cout << ptr 1->item << ""; cout << ptr 2->item << ""; cout << top->item << endl;

Now, the above code will make ptr1 to point next node of top, i.e., node with value R. And ptr2 will point to it's next node, i.e., node with value F. Top remains same at node with value S.

So, R, F and S are printed.