ANS::
as for given data
Note: JoeJoepp's solutions are very wrong - as they usually are. He clearly does NOT know stats that well. :(
(a)
Correlation between price and horsepower that does NOT
incorporate country
--> look at Model #1
--> SST = SSR + SSE = 4604.7 + 1604.44 = 6209.14
--> R^2 = SSR/SST = 4604.7/6209.14 = 0.7416 or 74.16%
--> r = (sign of the slope) x sqrt(R^2)
--> r = + sqrt(.7416)
--> r = +0.861
--> Answer: r = +0.861
(b)
Note: JoeJoepp's solution to this problem is wrong.
LS estimate of an American car with a 100 horsepower
engine
--> look at Model #2 that incorporates country
--> Predicted Price = -4.117 + 0.174 HP - 3.162 USA - 3.818
Japan + 0.311 Germany
--> Predicted Price = -4.117 + 0.174(100) - 3.162(1) - 3.818(0)
+ 0.311(0)
--> Predicted Price = 10.121
--> Answer: 10.121
Note: The units of y (although not stated) are probably in $1,000's. So, the correct answer could be
$10,121.
(c)
--> look at Model #2 that incorporates country
--> Since the outcome for Others is left out, the dummy
variables (aka indicator variables)
coefficients are relative to Others.
--> The coefficient for USA indicates that cars from the USA, on
average, are predicted to sell for
$3,162 LESS (since the coefficient is negative) than cars from
Others, holding HP constant.
--> The coefficient for Japan indicates that cars from Japan, on
average, are predicted to sell for
$3,818 LESS (since the coefficient is negative) than cars from
Others, holding HP constant.
--> The coefficient for Germany indicates that cars from
Germany, on average, are predicted to sell for
$311 MORE (since the coefficient is positive) than cars from
Others, holding HP constant.
--> Answer: Japan
(d)
Note: JoeJoepp's solution to this problem is wrong. He is doing 3 t-tests, when instead you need to do
a partial F-test.
Note:
* The global F-test tests all of the predictors at once.
* The t-tests tests the predictors individually.
* The partial F-test tests a group of predictors at once.
--> If we want to test whether the interaction terms are
significant, we have to do a partial F-test.
--> Model #3: Full model (with interaction terms): SSE =
1319.85, MSE = 16.0957
--> Model #2: Reduced model (without interaction terms): SSE =
1390.31
--> # of predictors being tested: 3 <-- we are testing the 3
interaction terms
Ho: The interaction terms are NOT significant
Ha: At least 1 of the interaction terms ARE significant
F = (change in SSE/# of predictors being tested)/MSE(FM)
F = ((1390.31-1319.85)/3)/16.0957
F = 1.4592
F-critical value: dfnumerator = 3 (we are testing 3 predictors) and dfdenominator = 82 (since we have
MSE of the full model in the denonimator). Using Excel, the
exact p-value is:
=F.DIST.RT(1.4592,3,82)
=0.231754934
Since the p-value = 0.232 > alpha = 0.05, do not reject
Ho.
--> Based on the sample data, there is INsufficient evidence to
indicate an interaction betweeen County
and horsepower.
Note: So, Model #2 (the model without the interaction terms) is clearly better and Model #3.
(e)
Note: JoeJoepp's solution to this problem is wrong. He is doing 3 t-tests, when instead you need to do
a partial F-test.
Note: Now that we decided that we didn't need the interaction terms, question (e) wants us to determine
whether we need the dummy variables.
--> Model #2: Full model (with HP and the dummy variables):
SSE = 1390.31, MSE = 16.3566
--> Model #1: Reduced model (with only horsepower): SSE =
1604.44
--> # of predictors being tested: 3 <-- we are testing the 3
dummy variables
Ho: The dummy variables for Country are NOT significant
Ha: At least one of the dummy varibles for Country ARE
significant
F = (change in SSE/# of predictors being tested)/MSE(FM)
F = ((1604.44 - 1390.31)/3)/16.3566
F = 4.3638
F-critical value: dfnumerator = 3 (we are testing 3 predictors) and dfdenominator = 85 (since we have
MSE of the full model in the denonimator). Using Excel, the
exact p-value is:
=F.DIST.RT(4.3638,3,85)
=0.00658462
Since the p-value = 0.007 < alpha = 0.05, we CAN reject
Ho.
--> Based on the sample data, there is sufficient evidence to
indicate that at least one of the dummy
variables for Country are significant.
Note: So, Model #2 is better than Model #1.
(f)
Note: JoeJoepp's solution to this problem is wrong.
Recall: Since the outcome for Others is left out, the dummy variables (aka indicator variables)
coefficients are relative to Others.
UsA --> p-value = .0216 < alpha = .05 --> Cars made in the USA are significantly cheaper (because the
coefficient for USA is negative) than those made in Other countries. Since USA is significant, we do
NOT want to combine USA and Other.
Japan --> p-value = .0061 < alpha = .05 --> Cars made in the Japan are significantly cheaper (because
the coefficient for Japan is negative) than those made in Other countries. Since Japan is significant,
we do NOT want to combine USA and Other.
Germany --> p-value = .8682 > alpha = .05 --> Cars made in the Germany are NOT significantly more
expensive than those made in Other countries. Since Germany is NOT significant, we should join Germany
and Others.
(g)
Note: JoeJoepp's solution to this problem is wrong.
After combining Germany with Other, Country now has 3 outcomes, i.e. USA, Japan and Other. So, now we need 3-1 = 2 dummy variables. This time leave off Japan* and the coefficients will be relative to Japan. Now, to test for a significant difference in price between American and Japanese cars, our t-test statistic would be:
t = coefficient for USA / s.e. for USA
----------------
I hope this helped. If you have any questions, please ask them in the comment section. :)
if you have any doubts pls comments bellow...pls rate positive rateings...
thank you....
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