Question

I need the answers ASAP

Apps Bookmarks ok Psycho-pass oog Tv Goals I Google o. lebtiger2011 Nikita S03E02 HDT. A particle with a charge of 5.0 pc is placed at the center of a cubical Gaussan surfece with side length 3 oom. Find the electric fux through one face of the cube. Need Help? A particle with a charge of 79.0 pct is at the center of a thin spherical shell fradius 16.0 cm that has unronm surface charge density e, Determine the value of e such that the net electric field outside the she change neutral square aluminum plate weh edge d- 31.o cm placed horizontally in a unronm electric meld or s so x 10 Ncdirected vertically, or in the tydrection. (a) What is the charge densty on each face of the aluminum plate? Cb) What is the total charge on each face of the eluminum plate? 5.00 Need Help?

Answer 1

1)

According to Gauss law the electric flux is given by

phi = Qin / epsilon not

phi = 5 * 10^-6 / 8.854 * 10^-12

for each face

phi = 1/6 * 5 * 10^-6 / (8.854 * 10^-12)

phi = 9.4 * 10^4 N-m^2/C

3)

a)

E = sigma / 2*epsilonnot

9.5 * 10^4 = sigma / (2*8.854*10^-12)

sigma = 1.68 *10^-6 C

upper face sigma = 1.68 *10^-6 C

lower face sigma = 1.68 *10^-6 C

b)

charge Q = sigma * A

Q = 1.68 *10^-6 * 0.31^2

Q = 0.16 * 10^-6 C

upper face Q = + 0.16 * 10^-6 C

lower face Q = - 0.16 * 10^-6 C

4)

a) at 5 cm E = 0 ( because no charge is present in side

b)

E = k * Q / r^2

E = 9 * 10^9 * 57 * 10^-6 / 0.44^2

E = 2649793.3 N/c