Question

A refrigeration plant that makes ice and supplies to local stores, maintains the cold room where the ice is made at -10 °F. The heat exchanger that transfers heat to the outside air operates at an average temperature of 100 °F. The heat of fusion for wateris -143 Btu/lbm. If 100 tons of ice is made per month, determine the minimum power requirement of the refrigeration unit. Note: 1 month = 30 days, 1 ton = 2,000 lbm

Answer 1

Given Tic-loºf: 449.67°R. TH = louef= 559.67°R mw=100 tonns a 100 X 2000 lbm: 2x10 s ebm, No. of days = N=30 N N . < ! To find] [Minimum power requirement (Winmin) ] Solution - - cop of the refrigeration unit The maximum value of will be: TL 449.67 (copi mara TH-TL 559.67- 449.67 Cop Jmex = 4.0883 8 max - W min. 4,078 Rate of heat removal from Water to form ice Now Gremoved time & removed U t = 30X24 X 60 X 60 ? = 2592X103 sec ) Now Gremoved - mapw (559.67 - 491.67) + mw lht mw epice (491.67 al -449.67) Herei Cpwa specificheat of water = 1 Btul abor (pice = specific heat of ice=0.49 Btulebor LH = heat of fusion of water = 143 Bruleb 4 491.670R - freezing point of water.

.: Premoved = 2X10SXIX (68) + 2x105x 14 3 + 2x105x0.49x42 Btu - Qremoved a t 463168103 Boty coa Gromoved 463168103 25 g 2x103 - 17-87 Btels. وليد N Wimin = 17.87 4.088 Bruls I wimin = 4.371 Bruls l (Ansi ,

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