Question

Using If and else and switch, how would you write code that would display 3 every time a 1 is rolled with any other numbered dice?

For example:

die roll 5, 1 = 3 , roll 4,1 =3 , roll 1,1 =3 and so on

die roll 1, 6 = 3 , roll 1, 4=3 , roll 1, 2= 3 and so on

Note: everything should roll the same unless a 1 is invovled

Thank-you

Answer 1

Solution:

suppose x and y are the variables holding the value of the rolling dice.

so the values which they will be holding is

int x, y = {1, 2, 3, 4, 5, 6};

switch(x)

{

case 1:

cout<<"3"<<endl;

break;

case 2:

if(y==1)

cout<<"3"<<endl;

break;

case 3:

if(y==1)

cout<<"3"<<endl;

break;

case 4:

if(y==1)

cout<<"3"<<endl;

break;

case 5:

if(y==1)

cout<<"3"<<endl;

break;

case 6:

if(y==1)

cout<<"3"<<endl;

break;

}

I hope this helps if you find any problem. Please comment below. Don't forget to give a thumbs up if you liked it. :)