Question

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Consider an adiabatic constant pressure batch reactor for the following ideal gas phase reaction: 2. A—В+С The reactor initial composition is of 50 mol% A and 50 mol% inert material. The initial reactor temperature is 300 K and the pressure is 101.325 kPa. The reaction rate is: -2,500 (-) kCwhere k=exp| Т The enthalpy of reaction can be assumed constant at -5,000 J/mol. The heat capacities are assumed to be constant, with the following values: В: 5 mol K A: 15 mol K and inert 15 C: 10 mol K mol K The desired fractional conversion of A is 90%. The initial reactor volume is 1 m2. Calculate the reaction time required and the final reactor volume..

Answer 1

Solution - A - B + Initial Mixture c Contains 150 mola). Do 50 malus. - Ineat) Nio=0.5 , To= 300k So NA = 0.5 -8A = KCA first order Reaction K= temp to find time Here T & Final is the Reactor Exit Volume. on adiabatic Constant Applying Energy Pressure batch balance Reactor Energy in - to Roh + Energy Q out st = + + Energy Ener Accumulation Generation die of Energy o 0+ (-AHR) (-8A) V + 6 = {Nicpi at

For adiabatic Reactor ä -o T-To = (-AHRT) NAC i dra Enici ENicei = NA CPA + NO Cers & Nelec & Ng CPI NA NA. (1-7A) No- NATA Ne= NAXA NINI. - [NAO (ITA)] COAT NAOTA CPB+ NAXA Cec + NICPI - NA CCA + NI. CPI – NATA (15) & NA FAC) + NAO XA (10) So SN, Cpi = NAICRA + NJ. Ces 0.5x 15+ 0.5x15 ( AHR(T)) = 5000 /mol T-300 = 5000 x 0.5 x 0.9 19 T= 450k - 0.003866 51 For First order Variable Velone Batch Reactor - ln (1-XA) = kot so t= - ln (1-0.g . ѕ ѕѕ. Tyr Jee 0.003866 Final volume v=V. (1+ CAXA) EA - YASA = 0.5x (2-1) = 0.5 V= 1*(1+0.5*0.9) JU= 1.45 m)