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11. Let X be a continuous random variable with density function fare-102 for 10 f(1) = lo otherwise where a > 0. What is the

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Answer #1

here for this to be valid :

\int_{0}^{\infty } f(x) dx must be 1

\int_{0}^{\infty } f(x) dx =\int_{0}^{\infty } ax2 e-10x dx =a*(-x2e-10x/10-2xe-10x/100-2e-10x/1000) |\infty0 =a/500 =1

a =500

for (d/dx)f(x) =(d/dx)*(500x2e-10x) =500*(2x*e-10x-10x2e-10x)

putting above equal to 0 ,

500*(2x*e-10x-10x2e-10x) =0

x =2/10 =0.2 =mode

therefore P(X>=mode )=P(X>=0.2) =1-P(X<=0.2)

=1-Jo f(x) dx =1-Jo500x2 e-10x dx =1-500*(-x2e-10x/10-2xe-10x/100-2e-10x/1000) |0.20 =1-0.3233

=0.6767

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