Answer
17.5903g
Explanation
The balanced equation for the reaction between sodium and chlorine is
2Na(s) + Cl2(g) ------> 2NaCl(s)
Stoichiometrically, 2moles of NaCl obtained from 1mole of Cl2
Number of moles = mass /molar mass
number of moles of NaCl obtained = 29.0g / 58.44g/mol =
0.4962mol
Number of moles of Cl2 gas reacted = 0.4962mol/2= 0.2481mol
mass = number of moles × molar mass
mass of Cl2 reacted = 0.2481mol × 70.9g/mol = 17.5903g
11.5 grams of soduim metal are placed in a container with excess chlorine omce thd reaction...
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