Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic...
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold alloy that contains 48 wt% Au and 52 wt% Ag. The densities of pure gold and silver are 19.32 and 10.49 g/cm3
Homework Answers
density of the resulting substance = 0.48*19.32 + 0.52*10.49
=14.73 g/cm^3
now, mass of 1 cm^3 os the alloy = 14.73 grams
so mass of gold in it = 0.48*14.73
=7.0704 grams
molar mass of Au = 197 g/moles
so number of moles = 7.0704/197
so number of atoms = 6.023*10^23*(7.0704/197)
=2.16*10^22 atoms/cm^3
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