Question

6.012 31.946 g g Part A: Calorimetry Data mass of calorimeter mass of calorimeter + water mass of water 44.969 34.089 g g 38.957 2.143 g mass of beaker mass of beaker + urea mass of urea molar mass of urea moles of urea g 60 g/n 22.650 0.0357 °C mol 18.720 original temperature final temperature temperature change °C 3.93 °C Part A: Calorimetry Calculations: 640.6 J heat absorbed or released legn. 1] heat absorbed or released per mole of urea (AH) Tegn. 21 -17.94 kJ/mol

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Answer 1

2 Part B: Spectrometer. Data e Calculations шт. Absorbance of saturated scen (Asat) = 0.148 absorbance of standard soren wrea Castel) = 0.512 Concentration g standard soen 0-1013 g1 Ls) 0.10139 urua un molecular cut o urea - 60 Il schn molarity no. of moles Volume Volume schn= of mores of urea? 0.1013. - molarity = 0.1013 = 0.001688 M Cetel schn 60XI Now, cone of saturated soln [Csat] = 20,000 X Cstelx Asat Astd of no us - 200 OXO-001688 x 0 148 0.512 Csat] = 9.7587M Thermodynamic calculation NH₂ CONH₂ (S) K NH2 CONH2 Laq? Turea) sp ke cone of product [NH2ONU,Jaq cone of reactant [NV₂ CONH2] for pure solid, [NH2CO NH] =1. - Ksp =[NH2 CONH2] [Csat 9.7587M SHOT ON REDMI Y3 AI DUAL CAMERA

Now, Free Energy change, AG = - RT en •RT enkgo where & Equilibrium constants 9.75 87 M R= 8.314 JJK) mar T= final temp. of system here z 18.720° - 18.720 +273 291.720 k. S9=-RT en kop - - 8.3148 291.720X 2-303 9-7587 5526-35173 - 5.526 35 173 kJ Now According to Gibbs Helmbotz egn: Su-TOS DH = 17.94 kJ/ma Ştre because endothermie? T= final temp = 18.720°C 18.720+273 291720k. AG=-5.52635173k J = - 5. 526 35173 = 17.94 - 291.720WS - 5.52635173-17.942 -291.720XAS +23.4663517 = 7291.720 XDS AS = 23.466 3517 291-720 DS=0.080 44 KJ/moll k SHOT ON REDMI Y3 20-080 44 X 100 AI DUAL CAMERA 94 J/mol K