Question

A certain radio station broadcasts at 105 megahertz. This is the frequency of oscillation of electrons in the transmitting antenna producing the radio wave. Find the period of the electrons' motion.

Answer 1

T = 1/f Given f = 105 mega Hz f = 105 times 10^6 Hz T = 1/105 times 10^6 T = 9.52380952 times 10^-9 seconds T = 9.52 times^-9 seconds T = 9.52 nanoseconds period of the electrons motion is 9.52 nanoseconds

$f = 105\times 10^{6} $ Hz$

$T = \frac{1}{105\times 10^{6}}$

$T = 9.52380952\times 10^{-9} $ seconds$

$T = 9.52\times ^{-9} $ seconds$