Question

PHY 201 Homework 07: density od osta Name For additional practice-especially with "ackage reacaning in the context of mass, volume, and density you may wish to try these additional problems (found on pp. 136-137): Supplementary Problems 9.1, 10.1, 10.5, 12.1. bola El San 1. If 80.0 mL of methanol and 80.0 mL of water are mixed, 1.00 cm of the mixture has a mass of 0.910 g. What are the mass, volume, and density of the whole mixture? (Based on Problem A.5 on page 142.) Notes: 3 LOL a) Methanol's density is 0.790 g/mL; water's density is 1.00 g/mL. b) This problem is intended, at least in part, to help you review some of your results from Section 7 of Properties of Matter. c) Finally, you may not use algebra in your solution. Instead, clearly explain the reasoning that you use for each step of multiplication, division, etc., in your solution. (For instance, every time you wurde divide, is the division based on "fair share" or "fit into" reasoning?) so s A

Answer 1

Volume of methanol = 80mL (VD Volume of water = 80mL (7 density of methanol = 0.79 g/mL (81) density of water = 19lmL (22) lemp = (10-2) Smaz lokm3 106m3 has a mass of 0.91g bet m, 8m, are the mass of methanal and water respectively, m = 20 = 80x0.79= 63.2g m2 22212 80 x 1 = 809 total mass (m) ='m, rm2 = 143.29 Let zis toral density & Vistoral volume, 24+242 = 20 Let the mixture have uniform Distribution of molecule. In new system, 30, 122.91 = 0.gt gleme) a temo

lema = 1 mL sog 2 = 0.91 g/mL & v= EN1T22V2 = 143.2 g 0.918/mL TV = 157.363 mL / Anstoer total mas 5 =143.29 tobal Volume=157.363 m2 total density = 0.91 g/mL