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3. [13+ 5 bonus points] Consider a plane ax + by + cz + d = 0 and a point P (x1, 71,z2) that is not on the plane. Please comp

Section 4.7 discusses Maximum and Minimum Values

Section 4.8 discusses the method of Lagrange Multipliers

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O. (ccocel) Let I be distance of pu 2) to the plane F (1, 2) = √(1-x) 4 (3-4, J7 (2-22 Such that awt by & CZ + d 20 The minim. х – 4 = -аа. . a(a+49) + c г, -о) e 4c1— - - - - - - ( 4 + 2 +са, се!) 2-22-dc rc (am of by trhad) амс L = a (amtby + Ch+d)o L (19) = TM-mrt (9-784 (2-272 : . where z=-d-an-by eto! if (min) = 6-) ? + (4-4,)*7 (-0-0-192722 = -1) 7(7-41) 7 (an of byt(a + (2) not aby + (acz, & ad- cm) 20 an + 6tyy + (bck, tod-ch) zo at(602, + 6d-en af (acz, & ad-de) - 6467 (achtad-c) - Cartif(win = (a2(am +by+chad) ? + 6hameby, echad) &ch (am abs, tchad) - Cont by a C2, e dja a 454c2 L (vin) = I amtby + c3 +d/ [Solution Equation of plame = ant by (2+d=0 P = (1 912) not in plane. Ø (m, 4, 2) = antbyt czad. Q = 10a edo edo hatib tuc The

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