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2. Separate from problem #1, we transfer 5 Joules into the internal energy of the pin, heating the pin to a new, higher temperature. If the pin has a specific heat capacity of 100 Joule per gram per Kelvin (J/kg K), by how many deegrees Kelvin will the pins temperature rise? (A) 50 K (B) 10 K (C) 5 K (D) 1 K (E) 0.01 K 3. Now lets transfer 5 Joules into sound waves. If the impact of the pin with the ground lasts 100 milliseconds, and all the kinetic energy (5 J for this problem), is transferred to sound within that time, what is the power of the sound? (A) 500 Watts (B) 50 Watts (C) 20 Watts (D) 0.02 Watts (E) 0.05 Watts

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Answer #1

3). Power is defined as work done per unit time.

Power = (energy/time)

Power = (5/100×10^-3)

Power = 50 watt.... option B is correct answer.

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