Question

Exercise 6110pts) Acceleration is sometimes measured in g. w here 10x-93 m/é, How many g's correspond is the steady acceleration of a car doing "zero to sixty"1 in 10.0 seconds? reaching a s the brakes (reaction time stop at the next light. The whole episode takes 150s. How far does the car travel? (Partial A: from a stop at a traffic light and acceterates at u rate of 4.0m/s2. Immedialely on peod of 32 m's, the driver sees that the next light ahead is red and instantly spplies C 0.00 s). The car decelerates at a constant rate and comes safely to a See the following figure.) Distance?

Answer 1

Given data initial velocity (v_initial) = 0 final velocity, (v_final) = 60 time = 10 seconds rightarrow acceleration is nothing but increase in the speed rightarrow the rate of change of velocity per unit of time acceleration = v_final - initial/time a = 60 - 0/10 = 60/10 a = 6 m/s^2 g�s = acceleration at 1.0g = 9.8 m/s^2 therefore g�s = 6/9.8 6m/s62 = 0.6122g