Question

The burner on an electric stove has a power output of 2.0 kW. A 610 g stainless steel tea kettle is filled with 20∘C water and placed on the already hot burner. If it takes 3.1 min for the water to reach a boil, what volume of water, in cm³, was in the kettle? Stainless steel is mostly iron, so you can assume its specific heat is that of iron.

Express your answer using two significant figures.
___cm³

Answer 1

energy = power*time=2*1000W*3.1*60sec=372000

heat gained= m_iron C_iron$\Delta T$ + m_w C_w$\small \Delta T$

=(0.610*450*(100-20))+(1000*V*4180*(100-20)) as mass=density*volume

heat lost= heat gained

372000=(0.610*450*(100-20))+(1000*V*4180*(100-20))

372000=21960+334400000V

350040=334400000V

V=1046.7 cm^3