At what distance from a long, straight wire carrying a current of 5.3 A is the magnetic ?eld due to the wire equal to the strength of Earth
magnetic field due to a striaght wire B = mu_0*i/(2*pi*R)...
given that B = 4.5*10^-5 T...
i = 5.3 A...
mu_0 = 1.25664*10^-6...
distance R = ?...
R = mu_o*i/(2*pi*B) =
(1.25664*10^-6*5.3)/(2*3.142*4.5*10^-5) = 0.0235 m = 2.35
cm
Biot-Savart Law - Magnetic field around a straight conductor carrying a current I.
B = ?_0 I/2?r
where:
B is strength of magnetic field in T.
?_0 is permeability of free space = 1.25664 x 10^ -6 T-m/A.
I is current in A.
r is distance from conductor in m.
So r = ?_0 I/2?B
r = (1.25664 x 10^ -6 T-m/A * 5.3A)/(2? * 4.5 x 10^ -5 T) = 0.02355
m = 2.3 cm
Apply B = uI/2pir
(4.5 X 10-5) = (1.25664 X 10-6)(5.3)/(2pi)(r)
r = .0236 m
That is 2.36 cm
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