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ovcr 55 who dream in black and whita is greater than the proportion for thoz under 25 Ccmplte parts (a) trough ic) beloww H1.1-P2 Identify the teet statistic. Rcund to twe decimal plac a ncedod. Paulus Rcund to three decimal places as nerdad.) เท at istha andusion based on the hypothesis tast The Pvali b. Teat the claim by conztructing an pprepriate confidence interval the signifcance leel oia-2.05, o huhypetheziz. There ia ▼ | evidence to support the darm that the proportion of people over 55 who cresm n blackand white is greater than the proportion for those under 25. What is the conclueion based on the conidence interva? inarval limits inclds c. An exclanation for the resuits is that those over the a of 55gw up exposed to media that was displayed in black and white. Can these resutsba used to verify that explanation? OA. No. Iha results speak to a poasibls dmarsnce between th proportiors ot peapls aver s and under 25 who dream In back and whits but the rasuts cannot be ursd to vertty the causs at such a diteranca O D. Yes The resuits can be used to verify the given explanarion bacause the cifferemnce in proportions is statisticalty signficant Cikk to sclect your answers)

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ct The sample size is n 303 The number of subjects isX1-74 The sample size is n, - 286 The number of subjects is X2-11 Sample proportion is p, - 303 0.244224422 P, ~O 244224422) Sample proporti on is p, 286 0.038461538 P, 0.038461538 Step1 State the null and alternative hypotheses In other words, we are to test whether p, is greater than p This can be written as p -P >0 Thus, the two hypotheses are Ho PP or P P2 0 (P, is equal to p2) 3 vefsus 71 Pi * P2 or(Pi is greater than p2) Step2 Select the distribution to use API,M%- Pa and z292 are all greater than 5, Consequently, both samples are large, and we use the normal distributi on to make the test Step3 Determine the rejection and non-rejection regions The > sign in the alternative hypothesis indicates that the test is right-tailed From the normal distributi on table, for a 0.05 significance level, the critical value of z is 1.645 for 0.05 area to the right

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Answer #1

ct The sample size is n 303 The number of subjects isX1-74 The sample size is n, - 286 The number of subjects is X2-11 Sample proportion is p, - 303 0.244224422 P, ~O 244224422) Sample proporti on is p, 286 0.038461538 P, 0.038461538 Step1 State the null and alternative hypotheses In other words, we are to test whether p, is greater than p This can be written as p -P >0 Thus, the two hypotheses are Ho PP or P P2 0 (P, is equal to p2) 3 vefsus 71 Pi * P2 or(Pi is greater than p2) Step2 Select the distribution to use API,M%- Pa and z292 are all greater than 5, Consequently, both samples are large, and we use the normal distributi on to make the test Step3 Determine the rejection and non-rejection regions The > sign in the alternative hypothesis indicates that the test is right-tailed From the normal distributi on table, for a 0.05 significance level, the critical value of z is 1.645 for 0.05 area to the right

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