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Practice Computing Hypothesis Test with a Computer In this worksheet we are going to focus on hypothesis test with the aid of
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media%2Fefe%2Fefecf5ba-416f-4da6-9336-4a

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

Ho: \mu_1 = \mu_2

Ha: \mu_1 \ne \mu_2

This corresponds to a two-tailed test, for which a t-test for two population means, with two independent samples, with unknown population standard deviations will be used.

(2) Rejection Region

Based on the information provided, the significance level is α=0.01, and the degrees of freedom are df=128. In fact, the degrees of freedom are computed as follows, assuming that the population variances are equal:

Hence, it is found that the critical value for this two-tailed test is tc​=2.615, for α=0.01 and df=128.

The rejection region for this two-tailed test is R={t:∣t∣>2.615}.

(3) Test Statistics

Since it is assumed that the population variances are equal, the t-statistic is computed as follows:

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(4) Decision about the null hypothesis

Since it is observed that ∣t∣=4.799>tc​=2.615, it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p=0, and since p=0<0.01, it is concluded that the null hypothesis is rejected.

(5) Conclusion

It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that population mean μ1​ is different than μ2​, at the 0.01 significance level.

Confidence Interval

The 99% confidence interval is 1.081<μ1​−μ2​<−0.319.

Graphically

normaldistributiongrapher.php?mean=0&sig

Please let me know in comments in case anything is unclear. Will reply ASAP. Do upvote if satisfied!

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