Question

question 3 please under problems

the cat measured along the ground. Also, determine the total flight time of the cat from launch to impact. Finally, determine the impact velocity of the cat with the ground. Newton's Laws: Questions: 1. If an automobile moving along a road at constant velocity experiences a force of 400 N in the forward direction, how much frictional force opposes the car's motion? Explain briefly. Problems: 1. (00) A 52 g bullet is fired horizontally from a rifle at 380 m/s into a water bottle at pointblank range. The bullet travels completely through the 12 cm long bottle, located 2 m above the ground. (You may assume there is no change in the height of the bullet while travelling through the bottle.) It finally hits the ground at a point 5 m downrange from the point where it left the water. Determine: a. the average force exerted by the water on the bullet. b. the total time elapsed from when the rifle is fired to when the bullet hits the ground. 2. (C) The famous tightrope walker, Tanya Toomuch, balances precariously in the middle of a 20 m long wire. As she stands there, the wire deflects a distance of 40 cm. a. Draw a free body diagram for the piece of wire just under Tanya's foot. b. If Tanya's mass is 60 kg, determine the tension in the wire. 3. A 30 kg crate of persimmons slides domh a rough 26° incline, and accelerates at 5 m/s a. Determine the normal force on the crate due to the incline. b. Determine the coefficient of kinetic friction 4. (00) A 6 kg block is pulled along a horizontal rough (uz = 0.5) surface by a massless string. The string then goes over a frictionless massless pulley and is attached to a vertically hanging block. Starting from rest assume static friction is overcome), the block moves 8 cm in 0.2 sec. Determine the mass of the hanging block. Newton's Theepot 1610 Work 74 ! 11 90 تو 4 % 5 * & 7 8 9 E E R. T Y U 0 Р

Answer 1

3rd N fik a Im mgsmo my cose N(Normal Force) = mg caso N = 30X9.8 x Cos (26) N= 264.24 (0) cii mg sino f= Чем from NLM MIN=ma mgsino - MK mg cosoma Mk= g sino a i come Mi= tano - gcoso Mic=tan(26)- 3 9.8X CO26) Mic= 0.147