[40 points] Here's a case where simple series/parallel tricks and voltage and current dividers all fail,...
[40 points] Here's a case where simple series/parallel tricks and voltage and current dividers all fail, and we have to go back to KVL, KCL, and Ohm's Law Given the circuit at right (resistors 1,2,3,4,5), calculate the equivalent resistance looking into the terminals. In other words, if you apply Vin and measure lin, then Rin Vin/Iin. (Although this may look like a Wheatstone bridge, we're not going to balance it.) Let's break it down one variable at a time. To start: a) Write I1, I2, I3, 14, and Is in terms of only Vin, Vi, and/or V2. For example, I2- (Vin- 2.00 3. Vinlin V2 VI 4.0 Q is OV V2)/20. b) Write Kirchhoff's Current Law for the top of the diamond: Iin c) Write KCL for I1 at the left corner of the diamond. d) Write KCL for I2 at the right e) Plug (c) and (d) into (b). f) ...And so on. Now eliminate remaining variables to find Rin Vin/Iin in terms of only corner of the diamond. the five given resistances.