How many grams of solid potassium hypochlorite should be added to 1.50 L of an 8.99×10-2 M hypochlorous acid solution to prepare a buffer with a pH of 8.453?
Grams potassium hypochlorite=
pKa of hypochlorous acid = 7.53
pH = pKa + log ( salt / acid )
Moles of hypochlorous acid = Molarity * volume
= 8.99*10^-2 * 1.50
= 0.13485
8.453 = 7.53 + log ( salt / 0.13485 )
Salt = 1.13
Mass = mole * molar mass
= 1.13 * 90.55
= 102.3215 grams
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How many grams of solid potassium hypochlorite should be added to 1.50 L of an 8.99×10-2...
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