If 2.50 g of aluminum nitrate (Al(NO3)3) reacts to form 1.83 g of solid aluminum sulfate, what is the percent yield?
2Al(NO3)3(aq) + 3(NH4)2SO4(aq) → Al2(SO4)3(s) + 6NH4NO3(aq)
If 2.50 g of aluminum nitrate (Al(NO3)3) reacts to form 1.83 g of solid aluminum sulfate,...
Aluminum metal reacts with sulfuric acid according to the following equation: 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(s) + 3H2(g) If 12.9 g of aluminum reacts with excess sulfuric acid, and 62.4 g of Al2(SO4)3 are collected, what is the percent yield of Al2(SO4)3?
3. Aluminum chloride reacts with sulfuric acid to form aluminum sulfate and hydrochloric acid according to the balanced chemical equation below. 2A1C13(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq) 133.340 g/mol 98.079 g/mol 342.150 g/mol 36.460 g/mol Molar Masses: a) How many grams of sulfuric acid react with 25.0 grams of aluminum chloride? b) What is the theoretical yield of HCl if sulfuric acid is in excess?
1. Zinc nitrate reacts with potassium phosphate to form the insoluble compound, zinc phosphate. The reaction proceeds according to the balanced equation below: 3 Zn(NO3)2 (aq) + 2 K3PO4 (aq) → Zn3(PO4)2 (s) + 6 KNO3 (aq) A mass of 0.1420 g is desired as the yield of zinc phosphate. Calculate the moles of desired product. 2. 2 Al(NO3)3 (aq) + 3 K2Cr2O7 (aq) → Al2(Cr2O7)3 (s) + 6 KNO3 (aq) Aluminum nitrate reacts with potassium dichromate to form the...
Problem 11.111 Review IC Part B Solid aluminum reacts with aqueous H, SO to form H, gas and aluminum sulfate. When a sample of Al is allowed to react, 370 mL of gas is collected over water at 23 °C, at a pressure of 790 mmHg. At 23 °C, the vapor pressure of water is 21 mmHg: 2Al(s) + 3H, SO. (ag) +3H2(g) + Al(SO4)3(aq) How many moles of H, were produced? Express your answer with the appropriate units. Value...
0 Chapter 7 Nov Solid aluminum sulfate is produced by reacting aluminum nitrate and potassium sulfate. The other product is aqueous potessium nitrate. 1. a) Write the balanced chemical equation. Be careful with naming. [Don't just google chemical formulael Use this as valuable practice for your naming. You can always check afterwards.1 If 109 g of aluminum nitrate and 0.626 moles of potassium sulfate are placed in a beaker, how many grams of solid could be formed? b) c) lf...
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? Al2(SO4)3(aq) Al(OH)3(s) H2O(l) H2SO4(aq)
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 g of magnesium bromide (MM - 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reactionDouble displacement 2115 MgBra (s) 2 AgNO (aq) > Mg(NO3)2(aq)...
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) a. Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.450 mol H2SO4 are allowed to react? b. How many moles of Al2(SO4)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?
If 3.40 g of aluminum hydroxide reacts with 1.25 g of sulfuric acid, what is the mass of water produced? Al(OH)3(s)+H2SO4(l)→Al2(SO4)3(aq)+H2O(l)
What is the percent yield of the solid product when 18.37 g of iron(III) nitrate reacts in solution with excess sodium phosphate and 3.526 g of the precipitate is experimentally obtained? Fe(NO3)3(aq) + Na3PO4(aq) --> FePO4(s) + NaNO3(aq) [unbalanced]