Solution:
We are given
Mean = 100
SD = 15
We have to find P(100<X<120)
P(100<X<120) = P(X<120) – P(X<100)
Z = (X – mean) / SD
For X = 120
Z = (120 – 100)/15
Z = 20/15
Z = 1.333333
P(Z< 1.333333) = P(X<120) = 0.908789
(by using z-table)
For X=100
Z = (100 – 100)/15
Z = 0
P(Z<0) = P(X<100) = 0.5
(by using z-table)
P(100<X<120) = P(X<120) – P(X<100)
P(100<X<120) = 0.908789 – 0.5
P(100<X<120) = 0.408789
Required probability = 0.4088
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