QUESTION 18 In the circuit represented in the figure below, 1,-1.00 A. Use Kirchhoff's loop rule...

Question

Question

Answer 1

Answer #1

I1=I2+I3 Using junction rule

I1=I2+1

18-7*I1-4*I3=0 using loop rule

18-7*I1-4*1=0

I1=2A

I2=1A

Answwr is second option

Answer 2

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