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Problem 18.16 2 of 3 Constants The radius ot the puley is 125 mm and the moment of inertia about its axis is I-0.05 kg- m. Pa

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At pulley Ey=Id (129) R = IX A - ATI AT T2 T3 = 0, 1250 0.05 4 479% 1 20x9.8 - Tz-T, = 3,2 a - At 4169 Efu = ma - Ti - 4x9.8=

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