Question

Question 18 Not compiete Marked out of 100 stripy rectangle in the second part of the diagram). The position of the end of the spring is now measured to be 59.9 cm. Fiag queston A 100.0 g mass is hung from a spring. A measurement is taken by using a ruler placed next to the spring to measure the position of the bottom of the mass carrier. This reads 55.0 cm. A additional mass of 40.0 g is added to the spring (the 0 cm 0 cm ruler ruler 100 cm 00 cm What is the spring constant for this spring? Nm1 Check Question 19 Nct compiere Marked out of 1.00 Another mass of 34.0 g is added to the spring. What is the reading on the ruler now? cm Flag question Check Question 20 Not compieta Marked out of 1.00 The hanging mass (with both the additional masses still present) is pulled down a short distance and released. What is the frequency of the oscillations of the hanging masses? Hz Flag queston Check

Answer 1

Question 18:

Let the spring constant is k

when an additional 40 g mass is attached to the spring.

The change in reading = 0.599 - 0.55 = 0.049 m

Now, k * x = m * g

k * 0.049 = 0.040 * 9.8

k = 8 Nm^-1

Qusetion 19:

If 34 g is added.

extra extension in spring = m * g/k

extra extension in spring = 0.034*9.8 / 8

extra extension in spring =0.042 m = 4.2 cm

Question 20:

As the motion will be simple harmonic

frequency = 1/(2pi) * sqrt(k/total mass)

frequency = 1/(2pi) * sqrt(8/(0.100 + 0.040 + 0.034)) = 1/2pi*6.780 = 0.023 Hz

frequency = 0.023 Hz