Question

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. At an intersection car B was traveling south and car A was traveling 30 north of east when they slammed into each other. Upon investigation, it was found that after the crash, the two cars got stuck and skidded off at an angle of 10° north of east. Each driver claimed that he was going at the speed limit of 50 km/h and that he tried to slow down, but couldn't avoid the crash because the other driver was going a lot faster. The masses of cars A and B were 1650 kg and 1350 kg, respectively, 10° ces 30 Determine the speed of the faster of the two cars if the slower car was traveling at the speed limit. The speed of the faster car was km/h

Answer 1

Assuming velice A is travelling sokular Given MA = 1650 kg MB = 1150kg Applying conservation of momentury to a plastic couition Emve = { uf Voi - WA vf sinio (2quo up its tout Vai a socostoi tso sinsad = 43.21 7 293 oi-vo ū - vas rūpse ve cos oît upozím jak momentury Conservation equation is Vai of mA Voi = MATUD) 4 (155089) (49-3 + 25 3) + 1550 Co-W;)= (165071350) r9 Upcostoit Eli, aus it 91,2509) 76-1150Upi*). seperating i and is condonents 71, 445 = 2940 Vf & vf = 24-3 41,270 - 1350 Via Slov VAT = 21:17 kullar since velice B comes in 21:17 Keather Locular this vehicle A driver lied we need to return the prostem with up rokullin costoit thi singo VA Vsi a o oi so Dat do Up Cassolit up, innos -

then momentum conservation equation is MAVA A mooi- two doi= matus) (lisong) (vti cossom VAI SALJÓS) + 1980 61 505) = (6ro +150) Up Colloit (lunguar 2940 vpi +5100 seperating 1419 vai = 2940uf & vf -0.48 Unti 825Vai- 67,500 5louf Vai = 63.09 kulhof Aug 3). Ve Sinio?) +825149)+ 67,000 i and 3 Components then f = 0.48 VAT) = 0.48*(63.09) Vj = 30.28 Keuther