Question

foundation please

CEG 4012: Foundation Engineering Design Project: TASK 1 Group D Develop a boring log by "hack-analysis based on the CPT data. Assume the water table to be at 2 m below the ground surface. This should include, as a minimum, the following components: 1. Soil classification with depth 2. Probable unit weights with depth 3. Effective stress with depth 4. Estimated N values with depth 5. Undrained Shear Strength and/or o values with depth Cone Resistance (MP) Local Side Friction foc (MP) Friction Ratio, R, () 203004 08 Ground Surface Elevation (m)

it is boring logs unsing back anaylisis for foundation engineering. please answer before 8 PM

Answer 1

Based on cone resistance and friction ratio, the soils were classified with below reference.

" Corrected cone resistance, qt [MPa] 2 0.1 TTT 0 1 2 34 5 Friction ratio, Rf [%] 6 7

SBT Soils Unit weight (kN/m?) 17.5 12.5 17.5 Sensitive fine grained Organic material Clay Silty clay to clay Clayey silt to silty clay Sandy silt to clayey silt | Silty sand to sandy silt 8 Sand to silty sand 9 Sand 10 Gravelly sand to sand 11* Very stiff fine grained* 12* Sand to clayey sand* *Overconsolidated or cemented. 18.0 18.0 18.0 18.5 19.0 19.5 20.0 20.5 19.0

Soil classification and unit weight, SPT N values with reference to CPT data is given below:

Rf-4,00-4/7 posandy bult to clayey failt V= 18 kell m3 &f=10&e=2 clay 3nt but kit.si 118.5 l RE=1, V = 3 o sulty and to handy mult am otio vened my Rf=5, V - 2 1 7 silty clay lemt v118.6 and the Red, Westo Selly beand to bandytact 15mtal Rf = 1, 00:30 it and to better and = 19.5 kilm Sand. I PE 19 KN don't R4 -1,96=10 2zm Feigl Imt šl Efertave kodus cuith difth Yr: 1842-36 Kulme Im - F - - = (1802) +(841) = 44 Kneline bm-ot de 36+ 8) + (17.5-10) # 3 = 66.5 Machine am.. If = 66,5 +(8.5*3) = 92 unelma 12m--- 20 = 12 + (8 + 3) = 116 Enelar ==116+ (8.5 + 3) = 141.5 Kilme dom- f = 1415+(945) = 186.5 Knult tag dasma d=186.5+ (9.5+ 3) = 245 dnem 15m - -

4 Estimation of ne values N-VC 0.4 Undua We as quen, wie fingt, for Each Layou 54 cmdluaoud tohuovu beteroth Cu= V e-Po Na Voz Con resenstance for Eauk layouloupe fig.) Por effecten istures confor trige) Tehual Calculation, Cu= (4x 18 -36) Alu: cone factor Consuedie Nk: 15 Cu = 264,3 kPa colulate teemelaely for Each ditth. $ ughus are calulotid focom suku e tego (Robudsen and Confavella.1983) I

om 8= 38 F- 8=36 0 N=10, Cu = 264.3 kPa 3mA =5 Cu=130.4 kPa om - N=8 Cu = 195.6 kPa am – N=5 Cu = 125. 6 Kla 1210 0-34 0-437 N=80 Cu - 1823. 9 apa 15m - N = 75 Cu = 1987.5 kPa 2010 - N=25 C = 65 2. 3 kPa I 23m. - - .8-381