A doubly ionized molecule (i.e., a molecule lacking two electrons), moving in a magnetic field, experiences a magnetic force of 5.09 × 10-16 N as it moves at 235 m/s at 65.3° to the direction of the field. Find the magnitude of the magnetic field.
F=qvBsin(theta)
q=is the charge on particle
v is the velocity
B is the magnetic field
F is the force
5.09*10^-16=2*1.6*10^(-19) *235 *B*sin65.3
B=7.45025T
A doubly ionized molecule (i.e., a molecule lacking two electrons), moving in a magnetic field, experiences...
A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.63×10−16 N as it moves at 287 m/s at 65.9∘ to the direction of the field. Find the magnitude of the magnetic field.
10. A doubly ionized molecule (i.e., a molecule lacking two electrons), moving in a magnetic field, experiences a magnetic force of 6.37 × 10-16 N as it moves at 361 m/s at 70.7° to the direction of the field. Find the magnitude of the magnetic field.
A double ionized molecule (i.e a molecule lacking two electons), moving in a magnetic field, experiences a magnetic force of 6.57×10^-16N as its moves at 393m/s at 71.9 degrees to the direction of the field. Find the magnitude of the magnetic field.
a doubly ionized molecule, moving into a nagnetic field, experiences a magnetic force of 6.01×10^-16 N as it moves at 251m/s at 67.5° to the direction of the field. find the magnitude of the magnetic field in T.
A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic force of 2.38 x 10* N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 5.44 m/s at an angle of 26.2° relative to the magnetic field. N What is the maximum force on a rod with a 0.100 C charge that you pass between the...
Problem 3. a. An electron moving at 4.00x103 m/s in a 1.25-T magnetic field experiences a magnetic force of 1.40*10-16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers. b. A proton moves at 7.50x107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.800 m. What is the field strength?
An electron moving with a speed of 8.8 x105 m/s in the positive z direction experiences zero magnetic force. When it moves in the positive x direction it experiences a force of 2.4 x10-13 N that points in the negative y direction. What is the magnitude and direction of the magnetic field? Magnitude: B= _____________T Direction: Magnetic field is pointed in ____________(indicate positive or negative) direction of ______________(indicate which axis i.e. x, y, or z) axis.
A proton moving in the positive x direction with a speed of 9.1 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 1.8 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field. magnitude T
What is the direction of the magnetic field? An electron experiences the greatest force as it travels 3.7 x 10° m/s in a magnetic field when it is moving northward. The force is vertically upward and of magnitude 6.5 x 10- N. West North East South Submit Request Answer Part B What is the magnitude of the magnetic field? Express your answer using two significant figures. 0 Ad Rom ?
A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.60 km/s in the +x-direction experiences a force of 2.10×10−16 N in the +y-direction, and an electron moving at 4.70 km/s in the −z-direction experiences a force of 8.60×10−16 N in the +y-direction. What is the magnitude of the magnetic field? What is the direction of the magnetic field? (in the xz-plane) What is the magnitude of the...