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Exercise 2.106.1 Prove that the map f: Q[V2 + Q[V2] that sends a + bv2 (for a, b, in the rationals) to a – bV2 is a ring isom
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Answer #1

Let R and S are rings. Then a ring homomorphis am is a function f : R S Such that Of(a+b) = f () + f(6) Haber ddition O prefeat Let atbra, care EQT] N LƯk + a, b, c, d 6 Now Flatbvo) + (c+d12)) of Care +b+d), 6) 3 a+c= (b +d) + = (a-be) + (c- dra) f1 i f( (a tova)(c + dve) of l ac + 2 bd + (bet ad) va) ac+2 bd - (bct ad 12 = fa-bre). (e-del = f (at bre) if (c + d rz). a tif (1+0.53) - 1-0, il: f(1) = 1 (11) is salisfied by f. Therefore f is a ring humomorphinas between out and all Lot f (atbi)for every atore E [VI]. (with a, b € ), a - bvT EDIT Such that fa- bie) fa+(br) - à-(b) ł = atbiz - This shows that f is suje

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Exercise 2.106.1 Prove that the map f: Q[V2 + Q[V2] that sends a + bv2 (for...
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