1. Find integers s, t such that 172s + 151t == 1. For full credit, find the smallest magnitude integers you can. Hint: First find gcd(151, 172) = 1.
`Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
By using extended eulidean algorithm,
Set up a division problem where a is larger than b.
a ÷ b = c with remainder R. Do the division. Then replace a with b,
replace b with R and repeat the division. Continue the process
until R = 0.
172 ÷ 151 = 1 R 21 (172 = 1 × 151 +
21)
151 ÷ 21 = 7 R 4 (151 = 7 × 21 + 4)
21 ÷ 4 = 5 R 1 (21 = 5 × 4 + 1)
4 ÷ 1 = 4 R 0 (4 = 4 × 1 + 0)
So, s=36, t=-41
Kindly revert for any queries
Thanks.
1. Find integers s, t such that 172s + 151t == 1. For full credit, find...
Discrete Math
Find d = gcd(131, 122). Find integers s and t such that d = 131 . s + 122-t
Using the Euclidean Algorithm show that gcd (193, 977) Now find integers s, t such that 193s +977t-1, and use this to find the value of a that satisfies the congruence 193a 38 (mod 977)
Using the Euclidean Algorithm show that gcd (193, 977) Now find integers s, t such that 193s +977t-1, and use this to find the value of a that satisfies the congruence 193a 38 (mod 977)
6. Using the Euclidean Algorithm show that gcd (109, 736) 1 Now find integers s, t such that 109s + 736t 1, and use this to find the value of r that satisfies the congruence 109x 71 (mod 736).
6. Using the Euclidean Algorithm show that gcd (109, 736) 1 Now find integers s, t such that 109s + 736t 1, and use this to find the value of r that satisfies the congruence 109x 71 (mod 736).
1 For each of the following pairs of numbers a and b, calculate and find integers r and s such ged (a; b) by Eucledian algorithm that gcd(a; b) = ra + sb. ia= 203, b-91 ii a = 21, b=8 2 Prove that for n 2 1,2+2+2+2* +...+2 -2n+1 -2 3 Prove that Vn 2 1,8" -3 is divisible by 5. 4 Prove that + n(n+1) = nnīYn E N where N is the set of all positive integers....
Solve the following question using Matlab language only.
Least common multiple (LCM) of two numbers is the smallest number that they both divide. For example, the LCM of 2 and 3 is 6, as both numbers can evenly divide the number 6. Find the LCM of two numbers using recursion Hint: You may assume that the first number is always smaller than the second number. Examplel First number for LCM:3 Second number for LCM 19 The LCM of 3 and...
Write a recursive method in java to find GCD of two integers using Euclid's method. Integers can be positive or negative. public class Recursion { public static void main(String[] args) { Recursion r = new Recursion(); System.out.println(“The GCD of 24 and 54 is “+r.findGCD(24,54)); //6 } public int findGCD(int num1, int num2){ return -1; } }
The least common multiple (lcm) of two positive integers u and v is the smallest positive integer that is evenly divisible by both u and v. Thus, the lcm of 15 and 10, written lcm (15,10), is 30 because 30 is the smallest integer divisible by both 15 and 10. Write a function lcm() that takes two integer arguments and returns their lcm. The lcm() functon should calculate the least common multiple by calling the gcd() function from program 7.6...
(1 point) Compute: gcd(72, 33)- Find a pair of integers x and y such that 72x + 33y gcd(72, 33)
(SHOW ALL WORK FOR FULL CREDIT) 1. Given a vector with a magnitude of 57 m/s and a direction 12 degrees, find the vertical and horizontal components of said vector.
PROBLEM 1 For each of the following pairs of integers, use the Euclidean Algorithm to find ged(a,b), and to write gcd(a,b) as a linear combination of a and b, i.e. find integers m and n such that gcd(a,b) = am + bn. (a) a = 36, b = 60. (b) a = 12628, b = 21361. (c) a = 901, b = -935. (d) a = 72, b = 714. (e) a = -36, b = -60.