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Image for 1. The A string on a violin should be tuned to 440 Hz. It. has a length of 0.500m and a mass density of 0.400
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Answer #1

Part A)

Apply v = f(wavelength) = sqrt (T/u)

(440)(2)(.5) = sqrt (T/4 X 10-4)

T = 77.4 N

Part B)

The next two harmonics will be at frequencies of 2f and 3f = 880 Hz and 1320 Hz

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