Question

3) Given the integral etdxanswer the following questions. a) Calculate Mo and So. b) Calculate the error bound for Mo usin K(b-a) 24n? c) How large should n be to guarantee the Midpoint Rule approximation is accurate to within 0.0001?

Answer 1

(3) Midpoint Rule: Sofrande Ž flais 4x = 4x [fray) + f(m) +- il - + fran) where an = bra aw ni = 2 Chirithi) midpoint of [i-1, hi). and ai = not iAx iron Here, f(as a en ne22 AX Kn axa ba sa s ģ .:/?franar a szex dxis Ax [f(ā) + f(āz) ...tot frão) a = otsį if (ū=f(t) = és tot 2 a ² fing) = f(²)= e sh 25+ I- flag) = $(5) - eng it als alumne if (g) = f(q)-e 46+ if(ā5) f(3) = 21% to 2 5672 = 16 flã6) 2f (46)= e36 36 % 25/32 40 la loro la gla 1 2. t 1 hala lvytlar ela te te 12 Le te alate 12/24 e Le Bore 4 te A3 104 12/26] .. cs Scanned with CamScanner Sell x 46-524.7.15.588.

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11 (6) Emlak cb-al- (ber3 XE[1,2] 24 HP / Sku K = A 24/1 Now, of(2)= ex 4.32022 ; f (x) a aixen : ::f!!(W2 4Xe? +2e Since of is monotone inereaning on [22] orefore if (2 has attain monimum KE 14"(2) | = 1664 + 2e9 s. 1829 Emolt ise at x=2. is yet 2 n=b ook . . Bilen 29.09g (6) Given (Emi <0.0001 31824:2* io <0. 34.72 . . a n i Getx10000 a my 1809.9 ina1810 CS canned with CamScanner