Question

Apply integration by parts twice to evaluate the integral. ſ in?(x15) dx correct value of ſin?(x+5) Choose the dx below. O A. x In? (x45) - 30x In (x15) + 15x + C O B. xIn? (x15) - 30x In (x15) + 450x+C O c. xIn(x15) + 450x In (x15) - 30x+C OD. xIn? (x+5) - 450x In (x15) + 450x + c

Answer 1

solution Sen?(23) de (as) da - Soccer www, wring entegration by farts . zeicens - jer) (1-1)" - Slencers 15.24 x) dx xkn²(x15) - x ln(x's) lize -|(2065). 15 - 20 ml.de 30 fences). da 30 a ln²(x's) again using integration by parts

xen?(x's) 30 1. ln(x's) dx. o frience 5 ( 2.2605 30 alo2(x15) den (xs). da Sida 7 di *]** is.x x = x 444(x's) - 30 of Me") - Ja 30.15 fl.de = zen [4'5) - 30 x 40 (X'S) + tc = x14x's) – 30x1067's) + 450 x