Question

Figure 2 shows a multiple op-amp networks combined to produce a gain amplifier circuit. For the given circuit: (i) Name all the type of op-amp circuits shown by Op-Amp 1 until Op-Amp 5. (ii) Calculate the output of each Op-Amp 1 until Op-Amp 4. Assume Vin = 10mV (iii) Determine the output voltage at the last Op-Amp 5. From this value, calculate the gain produced by this Op-Amp network in overall, by using Av=Vos / Vin equation. [10 Marks] CO3, PO1, C2) R2 = 2 k12 R8 = 8k12 R1 = 1 Rs = 4k 2 5 R = 2k12 R = 2 k2 Vin R3 = 2 k12 R7 = 4 k_2 Figure 2

Answer 1

type of ob- Amp op-Amp 1 are inverting op-Am op-Amp 2, and 3 are Voltage follower op - Amp Non-inverting of Amp- of Amp summing Amplifier 4 are are 5i رتن) 8 kn 2 kn 4kn Vo 1 M 5 + Vog ivin akn akn 2kn Vot 4kn for op Amp , then V-=0 V+=0, O - VUI - vin 1 + 2K Voja -2k vin Voq = -2K( lomu) V01-20V

then out put of Op-Amp 3, Voz = -20V for op- Amp 4, V+= lomu then V- = lom v ( Voz = lomv) (VO2 = V+ ) (V) – +(V4-4 2xn 2 kn 0 Va + V-- Vot 2 V- = Vot Vo4 = 2 ( lumV) Vot 2omv 2 for op Amp 5 V+=0 then V-=0 also V - Voz V- - Vu 4 4kn V-- Voz 2 kn + 0 V--VO 8 Kn + 4kn 2umu 0 + Vo 8K + 2-(-20) Akh (-20) 4x'a 2x^ 5 mV + 10V+ 5V Vo 8

V -3 IS - SX10 ܀ 8 Voz 8(15—0.005) 119.96 V Vo (liij Vo = 119.96V 119.96 V 3 11.996 8 10 Avz Vo vin 1omv Av= 1 1996 Note-o concept of virtual ground V+=V- And In fut impedance of op Amp is oo No current into the of Amp (during Applying KCL) so