a bicycle coasting at 9.0 m/s comes to a 5.0 m long, 1.5m high ramp.
what is the bicycles speed as it leaves the top of the ramp?
SOLUTION :
K. E. at the beginning of ramp = 1/2 m v^2 = 1/2 m (9)^2 = 40.5 m (N-m)
P. E at the top of the ramp = m g h = m * 9.8 * 1.5 = 14.7 m (N-m)
Let the speed at the top of ramp be V m/sec.
So K.E at the top of the ramp = 1/2 m V^2
So, aș per energy conservation :
Total energy at the beginning of the ramp = Total energy at the top of the ramp
=> 40.5 m = 14.7 m + 1/2 m V^2
=> 40.5 = 14.7 + 1/2 V^2
=> V^2 = (40.5 - 14.7) * 2 = 51.6
=> V = sqrt(51.6) = 7.18 m/sec
So, bicycle speed at the top of ramp = 7.18 m/sec (ANSWER).
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