A tank contains 1000L of brine with 40kg of dissolved salt. Pure water enters the tank at a rate of 10L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. Answer the following questions.
1. How much salt is in the tank after tt minutes?
Answer (in kilograms): S(t)=
2. How much salt is in the tank after 10 minutes?
Answer (in kilograms):
A tank contains 1000L of brine with 40kg of dissolved salt. Pure water enters the tank at a rate of 10L/min.
A tank contains 3,000 L of brine with 12 kg of dissolved salt. Pure water enters the tank at a rate of 30 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. (a) How much salt is in the tank after t minutes? y kg (b) How much salt is in the tank after 10 minutes? (Round your answer to one decimal place.) У kg Need Help? Read It Watch It Master It...
A tank contains 15,000 L of brine with 23 kg of dissolved salt. Pure water enters the tank at a rate of 150 L / min. The solution is kept thoroughly mixed and drains from the tank at the same rate.Exereise (a)How much salt is in the tank after t minutes?Exercise (b)How much salt is in the tank after 10 minutes?
(2 pts) A 150 L tank contains 100 L of pure water. Brine that contains 0.1 kg of salt/L enters the tank at 5 L/min. The solution is kept thoroughly mixed and drains from the tank at the rate of 4 L/min. Find the concentration of the salt in the tank at the moment it is full. (2 pts) Separate variables and use partial fractions to solve the following initial value problem. da T = x (- 1), x(0) =...
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the rate 13 L/min. Let y be the number of kg of salt in the tank after t minutes. The differential equation for this situation would be: dy dt = y(0) -
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L / min. The solution is mixed and drains from the tank at the rate 8 L / min.Let y be the number of kg of salt in the tank after t minutes.The differential equation for this situation would be:dy/dt=y(0)=
a tank contains 60 kg of salt and 2000 L of water. pure water enters at 6L/min the solution is mixed and drains at 9L/min y=kg of salt after t minutes. dy/dt=??? and y(0)=???
*1.5.36 A tank initially contains 90 gal of pure water. Brine containing 4 lb of salt per gallon enters the tank at 2 gal/min, and the (perfectly mixed) solution leaves the tank at 3 gal/min. Thus, the tank is empty after exactly 1.5 h. (a) Find the amount of salt in the tank after t minutes. (b) What is the maximum amount of salt ever in the tank? (a) The amount of salt x in the tank after t minutes...
(1 point) A tank contains 1600L of pure water. Solution that contains 0.08 kg of sugar per liter enters the tank at the rate 6 Umin, and is thoroughly mixed into it The new solution drains out of the tank at the same rate. (a) How much sugar is in the tank at the begining? (kg) (b) Find the amount of sugar after t minutes kg) c) As t becomes large, what value is y) approaching ? In other words,...
A tank contains 100L of water. A solution with a salt concentration of 0.6kg/L is added at a rate of 7L/min. The solution is kept thoroughly mixed and is drained from the tank at a rate of 5L/min. Answer the following questions. 1. If is the amount of salt (in kilograms) after t minutes, what is the differential equation for which y is satisfied? Use the variable y for y(t). Answer (in kilograms per minute): dy/dt = 4.2-(5y/100+2t) 2. How...
Only need answer for b.). Please show your work! A tank contains 70 kg of salt and 1000 L of water. Pure water enters a tank at the rate 10 L/min. The solution is mixed and drains from the tank at the rate 5 L/min (a) What is the amount of salt in the tank initially? Preview (kg) amount-70 Find the amount of salt in the tank after 1.5 hours. * Preview (kg) amount - 69.47696384 (c) Find the concentration...