Question

Objectives: Understand the 1-dimensional kinematics. Exercise a case with constant acceleration and constant speed Exercise some algebraic skills. Kinematics: One Dimension - Constant Acceleration: Additional Problems to Sample Problem 2.04 A cat and a motorcycle are racing from rest. The motorcycle first takes the lead because it (constant) acceleration am = 8.40 m/s^2 is greater than the cars (constant) acceleration , ac = 5.60 m/s^2, but it soon loses to the car because it reaches its greatest speed vm = 58.8 m/s before the car reaches its greatest speed vc = 106 m/s. After working on the Sample Problem on page 25. answer problem below. Obtain the position of the motorcycle as a function of time. xm(t) after the car catches. After working on the Sample Problem on page 25. answer problem below. Obtain the position of the motorcycle as a function of time. xm(t) after the car catches. After tm = 7s. the motorcycle is running with the constant velocity of vm, so it will be a linear equation with the slope of vm; xm(t) = vmt + b, where b is the y-intersection. By using the position xm(7 s) = 1/2 am t^2m = 205.8 at tm, when the motorcycle stops accelerating and starts running with the constant velocity of vm, you can get b = -205.8 m (Check this process yourself.) In summary. xm(t) = (58.8 m/s)t - 205 m. where b is the y-intersection. By using the position xm(7 s) = 1/2 am t^2m = 205.8 at tm, when the motorcycle stops accelerating and starts running with the constant velocity of vm, you can get b = -205.8 m (Check this process yourself.) In summary. xm(t) = (58.8 m/s)t - 205 m. Where does the car catch up the motorcycle from the starting position? What is the velocity of the car when it catches the motorcycle? When do both the car and motorcycle have the same velocity? Obtain the distance between the car and motorcycle what they are at the same velocity.
Please help with 4 and 5

Answer 1