a)
from hypergeometric distribution: probability that exactly 10
from second edition P(X=10)==0.2172
b)
P(at least 10 from second edition)=P(X>=10)=0.4406
c)
P(at least 10 from second edition)=P(at least 10 from 1st )+P(at least 10 from 2nd edition )=0.4532
d)
mean =nk/N =15*40/65=9
std deviation =(nk/N*(1-k/N)*(N-n)/(N-1))1/2 =1.665
e)
mean=15-9=6
std deviation =1.665
( please revert fr any clarification required)
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