Question

At room temperature, the equilibrium number of vacancies in pure aluminum is one vacancy every 107...

At room temperature, the equilibrium number of vacancies in pure aluminum is one vacancy every 107 atoms. Pure aluminum is heated to 650 oC where it has 1 vacancy every 1000 atoms at equilibrium. The crystal is then rapidly quenched to room temperature to prevent any vacancy from escaping or from reaching the equilibrium number of vacancies. After this rapid quenching, the density is accurately measured and found to be 2.698 g/cm3.

(i) Compare this density with the theoretical density for aluminum at room temperature.
(ii) What is the ratio of vacancies per 1000 atoms in the quenched crystal at room temperature? Given: Al is FCC with lattice constant of 0.4049 nm.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
At room temperature, the equilibrium number of vacancies in pure aluminum is one vacancy every 107...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In pure copper at room temperature there is about one atom vacancy every atom sites. At...

    In pure copper at room temperature there is about one atom vacancy every atom sites. At the metling temperture (1083 centigrade), there is about one vacanvy every sites. Question: What fraction of the volume change that takes place when the crystal is heated from room temperture to its metling temperature is due to the presence of vacancies? The linear thermal expansion coefficient of copper is

  • 2) (a) Calculate the equilibrium vacancy concentration (number of vacancies per m) for copper at 1000K...

    2) (a) Calculate the equilibrium vacancy concentration (number of vacancies per m) for copper at 1000K given that copper has an FCC structure with a lattice parameter a 3.597 A and a vacancy formation energy Q,-0.9 eV. Boltzmann's constant is 8.61733x10 eV/K (b) Plot the vacancy fraction as function of temperature in the range 100-1100K)

  • a.) Calculate the equilibrium number of vacancies per cubic meter in pure copper at 500 C....

    a.) Calculate the equilibrium number of vacancies per cubic meter in pure copper at 500 C. The vacancy formation energy for copper is 0.90 eV and its density is 8.96 Mg/m b.) What is the corresponding vacancy fraction at this temperature? 2.) Compare and contrast spatial ordering in a glass with that in a crystalline solid. Which system exhibits long-range order?

  • --Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature...

    --Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature ( C ) = 1017 Metal A = Tin Equilibrium Number of Vacancies (m-3) = 6.02E+23 Temperature for Metal A = 369 Metal B = Gallium 1) If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm3? Write your answers in Engineering Notation.          ...

  • Given Values Atomic Radius (nm) = 0.18 FCC Metal = Silver BCC Metal: = Sodium Temperature...

    Given Values Atomic Radius (nm) = 0.18 FCC Metal = Silver BCC Metal: = Sodium Temperature (c) = 1127 Metal A = Zinc Equilibrium Number of Vacancies (m^-3) = 7.42E + 23 Temperature for Metal A = 247 Metal B = Calcium If the atomic radius of a metal is the value shown above and it has the face-centered cubic crystal structure, calculate the volume of its unit cell in nm^3 Your Answer = What is the atomic packing factor...

  • Question 8 Pure silicon at room temperature has an electron number density of about 5 ×...

    Question 8 Pure silicon at room temperature has an electron number density of about 5 × 1015 m3 and an equal density of holes In the valence band. Suppose that one of every 10° silicon atoms is replaced by a phosphorus atom. (a) Which type will the doped semiconductor be, n or p? (b) What charge carrier number density will the phosphorus add? (c) What is the ratio of the charge carrier number density (electrons in the conduction band and...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT