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Coin with random bias. Let P be a random variable distributed uniformly over [0, 1]. A coin with (random) bias P (i.e., Pr[H]

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Answer:-

Given that:-

Given that P be a random variable distributed uniformly over[0,1] . A coin with bias P is flipped three times.

a.Let X_{i} be outcome of the flip a ith coin where i=1,2,3

The probability that all three flips are heads is

P(X_{1}=H,X_{2}=H,X_{3}=H)=\int_{0}^{1}P(X_{1}=H,X_{2}=H,X_{3}=H\setminus P=p)fp(p)dp

IN the question , the value of P does not change during the sequence of tosses, So

P(X_{1}=H,X_{2}=H,X_{3}=H)=\int_{0}^{1}P(X_{1}=H),P(X_{2}=H),P(X_{3}=H)fp(p)dpP(X_{1}=H,X_{2}=H,X_{3}=H)=\int_{0}^{1}p^{3}dp

P(X_{1}=H,X_{2}=H,X_{3}=H)=\begin{bmatrix} \frac{p^{4}}{4} \end{bmatrix}^{1}_{0}

P(X_{1}=H,X_{2}=H,X_{3}=H)=\frac{1}{4}

b. The probability that the second flip is heads given that the first flip is heads

P(X_{2}=H\setminus X_{1}=H)=\frac{P(X_{2}=H,X_{1}=H)}{P(X_{1}=H)}

P( X_{1}=H)=\int_{0}^{1}P(X_{1}=H\setminus P=p)fp(p)dp

P( X_{1}=H)=\int_{0}^{1}pdp=\frac{1}{2}

and

P(X_{1}=H,X_{2}=H)=\int_{0}^{1}P(X_{1}=H,X_{2}=H\setminus P=p)fp(p)dpP(X_{1}=H,X_{2}=H)=\int_{0}^{1}p^{2}fp(p)dp

P(X_{1}=H,X_{2}=H)=\int_{0}^{1}p^{2}dp=\frac{1}{3}

P(X_{2}=H\setminus X_{1}=H)=\frac{2}{3}

c.For independent,

P(X_{2}=H, X_{1}=H)=P(X_{2}=H)P(X_{1}=H)

P(X_{2}=H, X_{1}=H)=\frac{1}{3}

P(X_{2}=H)=P(X_{1}=H)=\frac{1}{2}

This show that

P(X_{2}=H,X_{1}=H)\neq P(X_{2}=H)P(X_{1}=H)

The second flip is not independent of the first flip.

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