Question

Question 25 75.0 g of PCI,(g) is introduced into an evacuated 3.00 L vessel and allowed to reach equilibrium at 250°C. PCI; (g) PCI; (g) + Cl (8) If K. = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? = 75.0 A) 2.88 atm 30.97+5(35.45 ) B) 2.27 atm = 0,360) mole C) 4.54 atm D) 7.42 atm E) 9.69 atm C HM 201/ Ghada El Zakhem Naous C= 0.360!=(0,120m N

Answer 1

No PUs gl - Pu contact pucg) Kp= 1.80 V= 32 T= 250°C = 250+273 $23k mass of pus lags 175g. moles = mass malay maps. 75 0.36 208 Nowo, PV=nRT Px3 = 0.36x0.0821 x 523 P = 5.15 atm Pas ' P Q + 5.15 (5.15-2) x x Kp = (Pela) (Peen) to At (Peas)

x² Р (5.15-2) x² 5.15-n = 1.8 x'+ 18x - 9.27=0. X=2.27 atm. Total presure = (5.15- - 5.15+n - 5.15+ 2.27 - 7.42 atom
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