How to solve the question/formula below?
I know 3! can be canceled by factors of 11!
but I dont know how to deal with 2! 2!.
Detailed explanation and exaction solution are needed. Thank you.
Homework Answers
`Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
Since it is 11!/(3!*2!*2!)
We know the 2!=2*1=2. Also 11!/3!=11*10*9*8*7*6*5
So, it is 11*10*9*8*7*6*5/(2*2)=11*10*9*2*7*6*5=415800
Kindly revert for any queries
Thanks.
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