Question

Logistic model

A population grows according to a logistic model with a carrying capacity of 10000. An initial population of 100 grows to 1000 in 100 hours. How long will it take for an initial population of 100 to grow to 9000.

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Answer #1

SOLUTION :


Growth model is :


P = Po e^(kt)

=> P/Po = e^(kt)

=> 1000/100 = e^(k * 100) 

=> 10 = e^(100 k)

Taking natural logarithm :

=> ln(10) = 100 k

=> k = ln(10)/100 


When P = 9000.

=> P/Po = 9000/100 = 90 


Let time taken be t hours for growing to 9000 from 100.


So,


P/Po  = e^(ln(10)/ 100 * t) 

=> 90 = e^(ln(10)/100 * t)

Taking ln :

=> ln(90) = ln(10)/100 * t

=> t = 100 ln(90) / ln(10) = 195.42 hours 


To grow to 9000 from 100, it will take = 195 .42 hours (ANSWER).

answered by: Tulsiram Garg
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