Question

Solve the equation for all degree solutions and if 0° < θ < 360°. Do not use a calculator. (Enter your answers as a comma-separated list. If there is no solution, enter NO SOLUTION.) 2 sin -V3 (a) all degree solutions (Let k be any integer.) (b) 00 s 360°

Answer 1

$\\2\sin \theta -\sqrt 3=0\\ \Rightarrow \sin \theta=\frac{\sqrt 3}{2}\\\\ \theta = (60+360 k)^o, (120+360 k)^o\\ \theta =60+360k,120+360 k \\\\ b)\ For\ 0^o\leq \theta <360^o \Rightarrow \theta =60^o,120^o\\$