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A 0.608 g sample of a protein was dissolved in 25.00 mL of water and the resulting osmotic pressure at 305 K was measured at
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Answer #1

first write the osmatic pressure formula and then calculate the molar mass as follows

KKT Uber salufin nelas2 mass olov megs mass RKT Molarma TTXCtN goluk Molavmas 0.608 x0.02206x20 O.00SoxD.02. l4200.un Fe Vott​​​​​​​

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